Quote:
Originally Posted by Luckeh!!!!
I dont have 3b*(sin(c))^2*cos(c)
i have 3b*(sin(b))^2*cos(b) though :/
that doesn't make a difference tohugh does it? or have I done another thing wrong?
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Look in the middle of your notes, where it says
3(sin(c))^2*cos(c) = ((sin(b))^3 - 0)/(b-0)
This gives
3b*(sin(c))^2*cos(c) = (sin(b))^3
If you're not familiar with the unit circle (which you should be), here's a link from Mathworld
Unit Circle