Planetarion Forums

Kurashima · 2 May 2005, 17:35

Can anyone else explain to me why this is funny?

Quote:

Originally Posted by Some Sig on another Forum

Your Mom is so fat, if she was a c variable, her initialization would look like this: yourMom = (TFAT*) malloc(sizeof(YOUR_MOM)); //Stack Overflow

Knight Theamion · 2 May 2005, 17:37

unlimited fatness, i guess

JonnyBGood · 2 May 2005, 17:40

I hope that guy's parents are dead.

queball · 2 May 2005, 17:48

It's not funny. malloc allocates memory from the heap, not the stack. It should be:
"Can anyone fix my code? I did alloca(sizeof(YOUR_MOM)) but got a stack overflow.

"

Marilyn Manson · 2 May 2005, 17:53

queball's stack could overflow on me anytime.

Knight Theamion · 2 May 2005, 17:54

queball wins

Cannon_Fodder · 2 May 2005, 18:10

Oh dear..

Cannon_Fodder · 2 May 2005, 18:14

There are 10 types of people. Those who understand binary, and those who dont.

*cry*

Baron Morte · 2 May 2005, 18:16

Oh my

I do enjoy this kind of humour. Like that one "theres no place like 127.0.0.1!theres no place like 127.0.0.1!theres no place like 127.0.0.1!theres no place like..."
Keep 'em coming!

Vaio · 2 May 2005, 18:25

Quote:

Originally Posted by Baron Morte

Oh my

I do enjoy this kind of humour. Like that one "theres no place like 127.0.0.1!theres no place like 127.0.0.1!theres no place like 127.0.0.1!theres no place like..."
Keep 'em coming!

Shouldn't it be 'There's no place like /home' ?

Why would anyone want to go to localhost ?

~Vaio~

Marilyn Manson · 2 May 2005, 18:46

This thread is so geeky it would be laughed at by Egon Spengler.

Weeks · 2 May 2005, 18:50

Quote:

Originally Posted by queball

It's not funny. malloc allocates memory from the heap, not the stack. It should be:
"Can anyone fix my code? I did alloca(sizeof(YOUR_MOM)) but got a stack overflow.

"

Damn you're sexy.

Marilyn Manson · 2 May 2005, 18:51

Weeks, you're a raging closet bi.

Weeks · 2 May 2005, 18:52

OK!!

Marilyn Manson · 2 May 2005, 18:53

Posting 'OK!!' doesn't make it any less true.

Weeks · 2 May 2005, 18:55

OK!!!

JonnyBGood · 2 May 2005, 18:56

It's a big party and every possible function is having fun, chatting and drinking. In an n-dimensional corner e^x stands bitter and alone. Near the lonely little one there's a small group of exponential functions, one of which is 2^x . 2^x turns around to see e^x on it's own in the corner. "Hey, e^x, come-on, integrate yourself", said 2^x pointing to the group. "What for?" whispers e^x "it makes no difference".

<3

Weeks · 2 May 2005, 19:01

Can I join the inner circle now?

Marilyn Manson · 2 May 2005, 19:04

Quote:

Originally Posted by Weeks

Can I join the inner circle now?

You have to be ritually sodomised first.

Weeks · 2 May 2005, 19:06

I've already had to put up with you wanting everyone to be bi, does that count?

Leshy · 2 May 2005, 19:06

Quote:

Originally Posted by Marilyn Manson

You have to be ritually sodomised first.

Which we all know is just a matter of time, not of choice.

JonnyBGood · 2 May 2005, 19:06

Sooner or later, time vill tell.

Marilyn Manson · 2 May 2005, 19:10

Quote:

Originally Posted by Weeks

I've already had to put up with you wanting everyone to be bi, does that count?

Have you had Leshy insert his penis into your bottom as you both crouch in the middle of a pentagram in the middle of a marble floor whilst all the moderators and admins do gregorian chants in hooded robes, and equally hooded 'lesser' forums members light ritual candles to illuminate the controlled ritual darkness?

Marilyn Manson · 2 May 2005, 19:10

Quote:

Originally Posted by JonnyBGood

Sooner or later, time vill tell.

CHRONOPADDY!

TheRat · 2 May 2005, 19:20

Quote:

Originally Posted by JonnyBGood

It's a big party and every possible function is having fun, chatting and drinking. In an n-dimensional corner e^x stands bitter and alone. Near the lonely little one there's a small group of exponential functions, one of which is 2^x . 2^x turns around to see e^x on it's own in the corner. "Hey, e^x, come-on, integrate yourself", said 2^x pointing to the group. "What for?" whispers e^x "it makes no difference".

<3

Seriously, that joke makes me horny

Weeks · 2 May 2005, 19:23

Careful there, carry on down that road Marilyn'll demand you out yourself as bi-sexual.

Marilyn Manson · 2 May 2005, 19:24

But Weeks is curious about the cock. This is my point.

Weeks · 2 May 2005, 19:27

Hey, I can use bold-type as well !

Why do you care so much?
That's a bit odd, isn't it?

Marilyn Manson · 2 May 2005, 19:29

Quote:

Originally Posted by Weeks

Why do you care so much?

Sexually harrasing men is a bit of a hobby of mine.

MrL_JaKiri · 2 May 2005, 19:29

Quote:

Originally Posted by JonnyBGood

Sooner or later, time vill tell.

BzzzzzzzzzCHCHK.

Weeks · 2 May 2005, 19:31

Quote:

Originally Posted by Marilyn Manson

Sexually harrasing men is a bit of a hobby of mine.

Are you sure you're not a tory?

Marilyn Manson · 2 May 2005, 19:32

Quote:

Originally Posted by MrL_JaKiri

BzzzzzzzzzCHCHK.

At times like this you can't tell if Mark is malfunctioning or merely making some sort of obscure reference.

JonnyBGood · 2 May 2005, 19:33

I'm listening to the hell march right now and I can picture Soviet tanks rolling over civilians :)))

Marilyn Manson · 2 May 2005, 19:34

Quote:

Originally Posted by Weeks

Are you sure you're not a tory?

No, I'm a bi.

MrL_JaKiri · 2 May 2005, 19:38

Quote:

Originally Posted by Marilyn Manson

At times like this you can't tell if Mark is malfunctioning or merely making some sort of obscure reference.

I was aiming for an onomatopoeic chronosphere noise.

Entium · 2 May 2005, 19:39

Quote:

Originally Posted by JonnyBGood

It's a big party and every possible function is having fun, chatting and drinking. In an n-dimensional corner e^x stands bitter and alone. Near the lonely little one there's a small group of exponential functions, one of which is 2^x . 2^x turns around to see e^x on it's own in the corner. "Hey, e^x, come-on, integrate yourself", said 2^x pointing to the group. "What for?" whispers e^x "it makes no difference".

Marilyn Manson · 2 May 2005, 19:40

Quote:

Originally Posted by MrL_JaKiri

I was aiming for an onomatopoeic chronosphere noise.

Oh, that's very good.

pig · 2 May 2005, 19:48

Still trying to get over the dissapointment that its "Geek humour" not greek humour, was looking forward to some greek humour for a weird reason.

Naps · 2 May 2005, 19:50

I think im just to dumb to get anything but Fart jokes :/

TheRat · 2 May 2005, 20:00

Quote:

Originally Posted by Naps

I think im just to dumb to get anything but Fart jokes :/

If you were referring to JGB's joke - Integrating e^x leave e^x - it doenst change

Appocomaster · 2 May 2005, 20:01

Quote:

Originally Posted by JonnyBGood

It's a big party and every possible function is having fun, chatting and drinking. In an n-dimensional corner e^x stands bitter and alone. Near the lonely little one there's a small group of exponential functions, one of which is 2^x . 2^x turns around to see e^x on it's own in the corner. "Hey, e^x, come-on, integrate yourself", said 2^x pointing to the group. "What for?" whispers e^x "it makes no difference".

<3

funny, but 2^x isn't an exponential function?

MrL_JaKiri · 2 May 2005, 20:02

Quote:

Originally Posted by Appocomaster

funny, but 2^x isn't an exponential function?

I think you should tell mathematics about that, it's obviously woefully misinformed.

TheRat · 2 May 2005, 20:03

Quote:

Originally Posted by MrL_JaKiri

I think you should tell mathematics about that, it's obviously woefully misinformed.

Isnt it a natural logarithm?

Naps · 2 May 2005, 20:07

cheers mrrat

its suddenly all become clear

*drools on self*

Appocomaster · 2 May 2005, 20:07

Apparently it is :/ I was getting all hooked up on e^x being the exponential function.

MrL_JaKiri · 2 May 2005, 20:08

Quote:

Originally Posted by TheRat

Isnt it a natural logarithm?

This may shock some people, but ln (x) isn't the same as 2^x.

TheRat · 2 May 2005, 20:09

Quote:

Originally Posted by MrL_JaKiri

This may shock some people, but ln (x) isn't the same as 2^x.

I'm talking about e^x.

JonnyBGood · 2 May 2005, 20:10

Quote:

Originally Posted by MrL_JaKiri

This may shock some people, but ln (x) isn't the same as 2^x.

Stop repressing people's freedom of expression you fascist!

MrL_JaKiri · 2 May 2005, 20:12

Quote:

Originally Posted by TheRat

I'm talking about e^x.

Taking natural logs is the inverse function of e^x, if that's what you mean. I'm still confused though.

TheRat · 2 May 2005, 20:13

Quote:

Originally Posted by mathworld.wolfram.com

The natural logarithm is the logarithm having base e

Ok, mybad. But close enough :P