Thread: Geek Humour
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Unread 3 May 2005, 10:17   #75
MrL_JaKiri
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Re: Geek Humour
Quote:
Originally Posted by Nantoz
2^x solved a briggsian logarithm then. lg(x). It is a exponetial function as far as I remember the definition: ka^x, where a is any positive, real number.
Did you put "Briggsian" in just to attempt to appear more intelligent, as it's utterly redundent when you're talking about "logarithms" as it is just the common logarithm.
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